factorize a²+ b²+ 2ab +2bc+ 2ca
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Here's your answer dude..
Step-by-step explanation:
The given expression can be factorized as given below:
a^2 + b^2 + 2ab +2bc +2ca
we can see that a^2 + b^2 +2ab is the expansion of (a+b)^2
=(a+b)^2 + 2bc + 2ca [Using the identity (a+b)^2 = a^2 + b^2 +2ab]
=(a+b)^2 + 2c (a + b)
[In the above step we can see that 2c is common between 2bc + 2ca so, the common term is written out side the bracket and the unlike terms are inside the bracket.]
=(a+b)^2+2c (a + b)
Hope you like this..
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