Math, asked by BrainlyHelper, 1 year ago

Factorize a2-b2-2b-1

Answers

Answered by Hacker20
67
a² - b² - 2b - 1

= a² - ( b + 2b + 1 )²

= a² - ( b + 1 ) ²

= a² -( b² + 1² + 2b1 )

= a² - b² + 1² +2b
Answered by mysticd
49

Answer:

 Factors \: of \\a^{2}-b^{2}-2b-1\\=(a+b+1)(a-b-1)

Step-by-step explanation:

 Factorisation \: of \\a^{2}-b^{2}-2b-1

=a^{2}-(b^{2}+2b+1)

=a^{2}-(b^{2}+2\times b\times 1 + 1^{2})

= a^{2}-\big(b+1\big)^{2}

/*By algebraic identity:

+2xy+ = (x+y)² */

=[a+(b+1)][a-(b+1)]

/* By algebraic identity:

-y² = (x+y)(x-y) */

= (a+b+1)(a-b-1)

Therefore,

 Factors \: of \\a^{2}-b^{2}-2b-1\\=(a+b+1)(a-b-1)

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