Question

factorize (a2-b2)3 + (b2-c2)3 + (c2-a2)3​

Answer 1

Answer:

By using the identity a³+b³+c³-3abc a=a²-b² b=b²-c² c=c²-a² if a+b+c=0 then a³+b³+c³=3abc On Adding we will get 0 => Ans would be= 3×(a²-b²)(b²-c²)(c²-a²) =(3)(a+b)(a-b)(b+c)(b-c)(c+a)(c-a)

Answer 2

Answer:

Here is your answer