Question

Factorize_ a²-b²-4ac+4c2

Answer 1

a²-b²-4ac+4c²=a²-2*2c*a+4c²-b²
=(2c-a)²-b²                                ................................{(x-y)²=x²+y²-2xy}
=(2c-a+b)(2c-a-b)                     ................................{x²-y²=(x+y)(x-y)}