Question

Factorize (a2-b2)
(c2-d2)-4abcd​

Answer 1

Answer:=(ac-bd+ad+bc)(ac-bd-ad-bc)

Step-by-step explanation:

$(a^2-b^2)(c^2-d^2)-4abcd=a^2c^2-a^2d^2-b^2c^2+b^2d^2-4abcd$

$=a^2c^2+b^2d^2-2abcd-(a^2d^2+b^2c^2+2abcd)$

$=(ac-bd)^2-(ad+bc)^2$

$=(ac-bd+ad+bc)(ac-bd-ad-bc)$

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