Question

Factorize:
a³x³-3a²bx²+3ab²x-b³

Answer 1

Answer:

Now,

a³x³ - 3a²bx² + 3ab²x - b³

= (ax)³ - 3(ax)²b + 3axb² - b³

= (ax - b)³,

using the identity

(x - y)³ = x³ - 3x²y + 3xy² - y³

= (ax - b) (ax - b) (ax - b),

which is the required factorization.