Question

factorize algebraic expression of 4(2a-3b)^2+8(2a-3b)​

Answer 1

Answer:

4(2a−3b)2+8(2a−3b)

Factor 4(2a−3b)

out of 4(2a−3b)2

.

4(2a−3b)(2a−3b)+8(2a−3b)

Factor 4(2a−3b)

out of 8(2a−3b)

.

4(2a−3b)(2a−3b)+4(2a−3b)(2)

Factor 4(2a−3b)

out of 4(2a−3b)(2a−3b)+4(2a−3b)(2)

.

4(2a−3b)(2a−3b+2)

Answer 2

QUESTION:-

✯ғᴀᴄᴛᴏʀɪᴢᴇ ᴀʟɢᴇʙʀᴀɪᴄ ᴇxᴘʀᴇssɪᴏɴ ᴏғ 4(2ᴀ-3ʙ)²+8(2ᴀ-3ʙ)

ANSWER✔

$\sf\therefore 4(2a-2b)^2+8(2a-3b)$

$\sf\implies (8a-8b)^2+(16a-24b)$

$\sf\therefore by\:using\:identity\:(a-b)^2=(a-b)(a-b)$

$\sf\implies \big( 4 \times (2a-3b)(2a-3b) \big)+8(2a-3b)$

$\sf\implies 4 \big( (2a-3b)(2a-3b)+4(2a-3b) \big)$

$\sf\implies 4 (2a-3b)(2a-3b+2)$

$\large{\boxed{\sf{ = 4 (2a-3b)(2a-3b+2))}}}$

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