factorize all of them!!plzzz fast
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In 1)&2) apply the sum of cube rule
i.e a³+b³= (a+b)(a²+b²-ab)
1)x³+4³ = (x+4)(x²+16-4x)
2) 27x³+125y³
= (3x)³+(5y)³ = (3x+5y)[(3x)²+(5y)²-(15xy)]
In 3)&4) apply
a³-b³ = (a-b)(a²+b²+ab)
3) 8x³-27y³
= (2x)³-(3y)³
= (2x-3y)[(2x)²+(3y)²+(6xy)]
4) 1-64a³
= (1)³-(4a)³
= (1-4a)[1+(4a)²+(4a)]
i.e a³+b³= (a+b)(a²+b²-ab)
1)x³+4³ = (x+4)(x²+16-4x)
2) 27x³+125y³
= (3x)³+(5y)³ = (3x+5y)[(3x)²+(5y)²-(15xy)]
In 3)&4) apply
a³-b³ = (a-b)(a²+b²+ab)
3) 8x³-27y³
= (2x)³-(3y)³
= (2x-3y)[(2x)²+(3y)²+(6xy)]
4) 1-64a³
= (1)³-(4a)³
= (1-4a)[1+(4a)²+(4a)]
Nightmare1069:
thanks ;)
my pleasure :)
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