Question

factorize and follow me please guys​

Answer 1

Answer:

$x^{2} + \frac{1}{x^{2}} - 2 - 3x + \frac{3}{x}$

$=( x^{2} + \frac{1}{x^{2}}-2\times x \times \frac{1}{x} )- 3\left( x - \frac{1}{x}\right)$

$= \left( x - \frac{1}{x}\right)^{2} - 3\left(x - \frac{1}{x}\right)$

$= (x - \frac{1}{x}) [ x-\frac{1}{x} - 3 ]$

Therefore.,

$\red { x^{2} + \frac{1}{x^{2}}-2-3x+\frac{3}{x} }$

$\green {= (x-\frac{1}{x})(x-\frac{1}{x} -3) }$

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