Math, asked by sakalakaboom555, 1 month ago

Factorize @ 16(m+n)³+16(m+n)²

pls give me the explaination.


the ans is this-16(m+n)²(m+n+1)​

Answers

Answered by GraceS
3

\sf\huge\bold{Answer:}

Given:

16(m+n)³+16(m+n)²

Solution:

To factorize 16(m+n)³+16(m+n)²

\fbox{◇Taking out 16(m+n)² common from the term◇}

we get,

16(m+n)²[(m+n)+1]

\fbox{Now,on simplifying the term}

we get,

16(m+n)²[m+n+1]

16(m+n)²(m+n+1)

So,by step by step explanation

on factorizing 16(m+n)³+16(m+n)²

we get 16(m+n)²(m+n+1) as solution.

Answered by itzheartcracker13
1

Answer:

\sf\huge\bold{Answer:}Answer:

Given:

16(m+n)³+16(m+n)²

Solution:

To factorize 16(m+n)³+16(m+n)²

\fbox{◇Taking out 16(m+n)² common from the term◇} </p><p>◇Taking out 16(m+n)² common from the term◇

we get,

16(m+n)²[(m+n)+1]

\fbox{Now,on simplifying the term}

Now,on simplifying the term

we get,

16(m+n)²[m+n+1]

16(m+n)²(m+n+1)

So,by step by step explanation

on factorizing 16(m+n)³+16(m+n)²

we get 16(m+n)²(m+n+1) as solution.

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