Question

Factorize b^2-9b+18?​

Answer 1

Answer:

${b}^{2} - 9b + 18 = 0 \\ {b }^{2} - 3b - 6b + 18 = 0 \\ b(b - 3) - 6(b - 3) = 0 \\ (b - 3)(b - 6) = 0 \\ b = 3 \\ b = 6$

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