factorize
b(c-d)²+a(d-c)+3(c+d)
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Answer:
b(c−d)
2
+a(d−c)+3(c−d)
=>b(c−d)
2
−a(c−d)+3(c−d)
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let's, => (c - d) = x
than the equation will be :-
\begin{gathered} = > b {x}^{2} - ax + 3x \\ \\ = > x(bx - a + 3) \\ \\ = > (c - d)[b(c - d) - a + 3]\end{gathered}
=>bx
2
−ax+3x
=>x(bx−a+3)
=>(c−d)[b(c−d)−a+3]
=> (c - d).(bc - bd - a + 3)
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