Math, asked by sanskaar30, 2 days ago

Factorize b²-ab(1-a)-a³

Answers

Answered by divyapakhare468
0

To factorize :   b^{2} - ab (1 - a ) - a^{3}

Solution :

  • To factorize  we write given expression in proper form :

            ⇒   b^{2} - ab + a^{2}b-  a^{3}

  • Now, by taking b common from first two terms and a  from last two terms we get,

          ⇒     b( b - a ) + a^{2}  ( b - a )

  • Again taking ( b - a )  as common we get,

          ⇒      ( b - a ) ( b + a^{2})

        Hence , factors of b^{2} - ab (1 - a ) - a^{3}  are    ( b - a ) ( b + a^{2})

Answered by junaida8080
0

Given equation is,

b^{2} -ab(1-a)-a^{3}

Now we have to factorize the given equation

b^{2} -ab(1-a)-a^{3}

b^{2} -ab+ a^{2} b-a^{3}

Now we have to take b common from first two terms and a^{2} common from last two terms.

We get the equation as,

b(b-a)+a^{2} (b-a)

Again take (b-a) common from both the terms.

(b-a)(b+a^{2} )

Therefore, the final answer after factorization is (b-a)(b+a^{2} )

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