Question

factorize by algebraic identity 4x²-4x+1​

Answer 1

Step-by-step explanation:

4x²-4x+1=0

=> 4x²-2x-2x+1=0

=> 2x(2x-1)-1(2x-1)=0

=> (2x-1)(2x-1)=0

Therefore

2x-1=0

x=1/2

Hope it helps

Answer 2

${4x}^{2} - 4x + 1 \\ {4x}^{2} - 4x + 1 = 0$

${4x}^{2} - 2x - 2x + 1 = 0 \\ 2x(2x - 1) - 1(2x - 1) = 0 \\ (2x - 1)(2x - 1) = 0 \\ {(2x - 1)}^{2} = 0 \\ 2x = 1 \\ therefore \\ x = \frac{1}{2} \\ hence \: l \: have \: used \: middle \: - \\term \: technique \: to \: factorise \: the \: equation$