Question

Factorize by common factor method : p2qr + pq2r + pqr2

Answer 1

The factorization of $p^2qr + pq^2r + pqr^2$ by common factor method is pqr(p + q + r).

Explanation:

We have,

$p^2qr + pq^2r + pqr^2$

To find, the factorization of $p^2qr + pq^2r + pqr^2$ by common factor method = ?

∴ $p^2qr + pq^2r + pqr^2$

= p(p)qr + p(q)qr + pq(r)r

= p(pqr) + q(pqr) + r(pqr)

Taking pqr as common, we get

= pqr(p + q + r)

∴ The factorization of $p^2qr + pq^2r + pqr^2$ by common factor method = pqr(p + q + r)

Thus, the factorization of $p^2qr + pq^2r + pqr^2$ by common factor method is pqr(p + q + r).