Question

Factorize by splitting the middle term:
$3 {y}^{2} - y - 14$
please answer ​

Answer 1

ANSWER✔

$\sf\implies 3 {y}^{2} - y - 14=0$

$\sf\implies 3y^2+6y-7y-14=0$

$\sf\implies (3y-7)(y+2)=0$

$\sf\implies 3y-7=0,y+2=0$

$\sf\implies 3y=7,y=-2$

$\sf\implies y= \dfrac{7}{3},-2$

$\large{\boxed{\bf{ \star\:\: y= \dfrac{7}{3},-2\:\: \star}}}$

________________

Answer 2

Answer:

➡ 3y² −y−14=0

=> 3y² +6y−7y−14=0

=> (3y−7)(y+2)=0

=> 3y−7=0,y+2=0

=> 3y=7,y=−2

=> y = 7/3 , -2✔

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Step-by-step explanation:

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