factorize by using algebraic identities a^2+14a+49
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Answered by
1
Answer:
I will not be able to get the answer
Answered by
4
Answer:
The factors are (a+7),(a+7).
Step-by-step explanation:
Given expression is
a²+14a+49
It can factorised as
a²+14a+49
=a2 +7a+7a+49
=a(a+7)+7(a+7)
=(a+7)²
Thus factors are (a+7),(a+7).
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