factorize by using identity x2-y2/100
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x²-y²/100
= (x²-y²)/10² [It is in The Form of (a²-b²)]
= [(x+y)/10] [(x-y)/10]
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= (x²-y²)/10² [It is in The Form of (a²-b²)]
= [(x+y)/10] [(x-y)/10]
Here is Your Answer
If You Like it
Please Mark as BrainList
Thanks
Amankhan993653:
@kirtan Pls Mark as BrainList
Answered by
18
x^2-y^2/100
=(x-y)(X+y)/100
={(x-y)/10}{(x+y)/10}
=(x-y)(X+y)/100
={(x-y)/10}{(x+y)/10}
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