Question

factorize by using suitable identities a^6+ 8a^3+16​

Answer 1

Step-by-step explanation:

(a^2)^3+(-2a)^3+3^3

=(a^2-2a+3)[(a^2)^2+(-2a)^2+3^2-a^2*(-2a)-(-2a)*3-3*(a^2)]-3(a^2)(-2a)*3

=(a^2-2a+3)[a^4+4a^2+9+2a^3+6a-3a^2]+18a^3