Question

factorize completely:-
a(b-c)+d(b-c)​

Answer 1

$\huge\sf\underline\red{Solution}$

Given a(b-c)+d(b-c) To factorise

From given equation we can take common (b-c)

So, a(b-c)+d(b-c) = (b-c)(a+d)

Answer 2

Step-by-step explanation:

a(b-c)+d(b-c)

= ab-ac+db-dc

=a(b-c)+d(b-c)

=(a+d)(b-c)