Question

factorize each binomial 2ab+4c​

Answer 1

Answer:

let 2ab + 4 c = x

then squaring on both sides

$(2ab + 4c) {}^{2} = (x) {}^{2}$

$4a {}^{2} b {}^{2} + 16c {}^{2} + 16abc = x {}^{2}$

$4a {}^{2} b {}^{2} + 16c(c + 16ab) = x {}^{2}$

then

$x {}^{2} - 16c(c + 16ab) - 4a {}^{2}b {}^{2} = 0$

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