Question

factorize each of the following expression. y²+20y+100​

Answer 1

Answer:

y2 + 2*10*y +10*10 = (y+10)2

Step-by-step explanation:

y2 + 2*10*y +10*10 = (y+10)2

Answer 2

Answer:  (y+10)(y+10) is the solution

Step-by-step explanation:

Given:y²+20y+100​

1) Make the skelton(y  )(y  )=0

2) Add the signs

(i)if all the terms are positive:(y+  )(y+  )=0

(ii)if the center term is negative:(y-  )(y-  )=0

(iii)if the last term is negative(y+  )(y- )=0

(iv)if both the middle term and last term is negative(y+  )(y- )=0

3)Find the factors for last term should equal the middle term

4)Check work with FOIL method

As mentioned above step:

1)Make a skelton

(y   )(y   )=0

2)(i)if all the terms are positive:

(y+  )(y+  )=0

3)Now, Find the factors for last term should equal the middle term

100 factors are=1 x 100, 10x10 and 2 x 50

y²+20y+100​=0

So,(y+10)(y+10)

=y^2+10y+10y+100

=y^2+20y+100

(y+10)(y+10) is the solution