Factorize each of the following expressions:
8x³ y³ +27a³
Answers
The algebraic expression is given as: 8x³ y³ + 27a³
= (2xy)³ + (3a)³
In order to factorise the given algebraic expression as the sum of two cubes we use the following identities - a³ + b³ = (a + b) (a² – ab + b²) :
Here a = 2xy and b = 3a
= (2xy + 3a) ((2xy)² - 2xy × 3a + (3a²))
= (2xy + 3a) (4x²y² - 6xya + 9a²)
Hence, the factorization of an algebraic expression 8x³ y³ + 27a³ is (2xy + 3a) (4x²y² - 6xya + 9a²).
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8x³ y³ +27a³
= (2xy)³ + (3a)³ [a³ + b³ = (a + b) (a² – ab + b²) ]
= (2xy + 3a) ((2xy)² - 2xy × 3a + (3a²))
= (2xy + 3a) (4x²y² - 6xya + 9a²)
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