Question

Factorize each quadratic expression.
a) p² - 4p-5​

Answer 1

Answer:

(p+1)(p-5)

Step-by-step explanation:

p² - 4p-5= p² +p - 5p-5= p(p+1) - 5(p+1)

= (p+1)(p-5)

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Answer 2

Factoring  p2-4p-5 

The first term is,  p2  its coefficient is  1 .

The middle term is,  -4p  its coefficient is  -4 .

The last term, "the constant", is  -5 

Step-1 : Multiply the coefficient of the first term by the constant   1 • -5 = -5 

Step-2 : Find two factors of  -5  whose sum equals the coefficient of the middle term, which is   -4 .

     -5   +   1   =   -4   That's it

Step-3 : Rewrite the polynomial splitting the middle te

rm using the two factors found in step 2 above,  -5  and  1 

                     p2 - 5p + 1p - 5

Step-4 : Add up the first 2 terms, pulling out like factors :

                    p • (p-5)

              Add up the last 2 terms, pulling out common factors :

                     1 • (p-5)

Step-5 : Add up the four terms of step 4 :

                    (p+1)  •  (p-5)

             Which is the desired factorization

Hope it $\huge \mathbb \orange {HELPS}$