factorize f(x)= x^2-6x^2 + 11x-6 using factor theorem
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Step-by-step explanation:
Let f(x) = x3 + 6x2 + 11x + 6 For x = -1 f(-1) = (-1)3 + 6(-1)2 + 11(-1) + 6 = -1 + 6 - 11 + 6 = 12 - 12 = 0 Hence, (x + 1) is a factor of f(x). ∴ ∴ x3 + 6x2 + 11x + 6 = (x + 1)(x2 + 5x + 6) = (x + 1)(X2 + 2x + 3x +6) = (x + 1)[x(x + 2) + 3(x + 2)] = (x + 1)(x + 2)(x + 3)Read more on Sarthaks.com - https://www.sarthaks.com/149986/factorise-x-3-6x-2-11x-6-completely-using-factor-theorem
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