Factorize following n^2 +2n -2n-8=0
Answers
Answered by
0
╒═════════════════════╕
☬ ★Your Answer★ ☬
╘═════════════════════╛
⇣⇣⇣⇣⇣⇣⇣⇣⇣⇣⇣⇣⇣⇣⇣⇣⇣⇣⇣⇣⇣⇣⇣⇣⇣⇣⇣⇣⇣⇣⇣⇣⇣
⏩n² +4n-2n-8 =0
⏩n(n+4)-2(n+4)
⏩(n-2)(n+4)
⏩by equating ,
⏩n = 2 , and -4
⏩Roots are 2 and -4
⇡⇡⇡⇡⇡⇡⇡⇡⇡⇡⇡⇡⇡⇡⇡⇡⇡⇡⇡⇡⇡⇡⇡⇡⇡⇡⇡⇡⇡⇡⇡⇡
╒══════════════════════╕
☬ Thanks ,hope you like it ! ☬
╘══════════════════════╛
☬ ★Your Answer★ ☬
╘═════════════════════╛
⇣⇣⇣⇣⇣⇣⇣⇣⇣⇣⇣⇣⇣⇣⇣⇣⇣⇣⇣⇣⇣⇣⇣⇣⇣⇣⇣⇣⇣⇣⇣⇣⇣
⏩n² +4n-2n-8 =0
⏩n(n+4)-2(n+4)
⏩(n-2)(n+4)
⏩by equating ,
⏩n = 2 , and -4
⏩Roots are 2 and -4
⇡⇡⇡⇡⇡⇡⇡⇡⇡⇡⇡⇡⇡⇡⇡⇡⇡⇡⇡⇡⇡⇡⇡⇡⇡⇡⇡⇡⇡⇡⇡⇡
╒══════════════════════╕
☬ Thanks ,hope you like it ! ☬
╘══════════════════════╛
Answered by
0
hope its help for you
plz mark me in brainlist answer
Radhe Radhe
plz mark me in brainlist answer
Radhe Radhe
Attachments:
Similar questions