Question

factorize it by using suitable identities​

Answer 1

(2+4x) whole cube(3)

8+3(4)(4x)+3(16xsquare)(2)+64x cube

8+48x+96x+64xcube

Answer 2

Question: Factorize $8+64x^{3}$

Solution:

$=2^{3}+(4x)^{3}$

This is in the form of $a^{3}+b^{3} = a^{3}+3a^{2}b+3ab^{2}+b^{3}$

$=2^{3}+3(2)^{2}(4x)+3(2)(4x)^{2}+(4x)^{3}$

$=8+48x+96x+64x^{3}$