Math, asked by damarnathpatro, 10 months ago

factorize it faster.​

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Answered by RishikaEinstein556
2

Answer:

x {}^{3}  + y {}^{3}  + xy(x + y)

x {}^{3}  + y {}^{3}  + x {}^{2}y + xy {}^{2}

Answered by Anonymous
1

Step-by-step explanation:

Given here

x³+y³+xy(x+y)

= (x+y)(x²+y²-xy)+xy(x+y)

= (x+y)(x²+y²-xy+xy)

= (x+y)(x²+y²)

[ we know , ]

(x³+y³)=(x+y)(x²+y²-xy)

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