Question

Factorize it maths question​

Answer 1

Answer:

$6 {x}^{2} + 2$

Step-by-step explanation:

$({x + 1})^{3} - ({x - 1})^{3}$

$= ({x}^{3} + {1}^{3} + 3 \times {x}^{2} \times 1 + 3 \times x \times {1}^{2}) -( {x}^{3} - {1}^{3} + 3 \times x \times {1}^{2} - 3 \times {x}^{2} \times 1)$

$= ( {x}^{3} + 1 + 3 {x}^{2} + 3x) - ( {x}^{3} - 1 + 3x - 3 {x}^{2})$

$= 1 + 3 {x}^{2} + 1 + 3 {x}^{2}$

$= 6 {x}^{2} + 2$