Math, asked by manitchitkara, 8 months ago

factorize it please​

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Answers

Answered by rishu6845
2

Answer:

( 2x + 3y ) ( 2x + 3y - 4 )

Step-by-step explanation:

Given---> ( 4x² + 12xy + 9y² - 8x - 12y )

To find---> Factors of given expression

Solution---> We know that

a² + 2 a b + b² = ( a + b )²

Now returning to original problem,

4x² + 12 xy + 9y² - 8x - 12 y

= ( 2x )² + 2 × 2x × 3y + ( 3y )² - 2× 4x - 3 × 4y

Applying above identity , we get

= ( 2x + 3y )² - 4 ( 2x + 3y )

Taking ( 2x + 3y ) common from both the terms, we get

= ( 2x + 3y ) { ( 2x + 3y ) - 4 }

= ( 2x + 3y ) ( 2x + 3y - 4 )

Addutional information--->

1) ( a - b )² = a² + b² - 2ab

2) ( a + b + c )² = a² + b² + c² + 2ab + 2bc + 2ca

3) a² - b² = ( a + b ) ( a - b )

4) ( a + b )³ = a³ + b³ + 3ab ( a + b )

5) ( a - b )³ = a³ - b³ - 3ab ( a - b )

Answered by Anonymous
21

Answer:

( 2x + 3y ) ( 2x + 3y - 4 )

Step-by-step explanation:

Given---> ( 4x² + 12xy + 9y² - 8x - 12y )

To find---> Factors of given expression

Solution---> We know that

a² + 2 a b + b² = ( a + b )²

Now returning to original problem,

4x² + 12 xy + 9y² - 8x - 12 y

= ( 2x )² + 2 × 2x × 3y + ( 3y )² - 2× 4x - 3 × 4y

Applying above identity , we get

= ( 2x + 3y )² - 4 ( 2x + 3y )

Taking ( 2x + 3y ) common from both the terms, we get

= ( 2x + 3y ) { ( 2x + 3y ) - 4 }

= ( 2x + 3y ) ( 2x + 3y - 4 )

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