Math, asked by aadiboxershorts, 1 year ago

factorize it please
step by step

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Answers

Answered by hukam0685
1
To Factorise :

Try to make a common factor by taking terms common ,as in the given question it 2 is taking common from first 2 terms,and pq from last two terms,it will be factorised

 = 8p + 8q + 4 {p}^{2} q + 4p {q}^{2} \\ \\ = 2(4p + 4q) + pq(4p + 4q) \\ \\ = (4p + 4q)(2 + pq) \\ \\ 8p + 8q + 4 {p}^{2} q + 4p {q}^{2}= 4(p + q)(2 + pq) \\ \\
or

Multiply 4 in the second bracket

 8p + 8q + 4 {p}^{2} q + 4p {q}^{2}= (p + q)4(2 + pq) \\ \\=(p+q)(8+4pq)

Hope it helps you.

aadiboxershorts: yes but the final answer will be
(p+q)(8+4pq)
hukam0685: you can let it be, it was correct
hukam0685: or send the 4 inside the second bracket
hukam0685: look Solution,I had edit
aadiboxershorts: 4xpq is 4pq bro
hukam0685: Oh yes,I was in hurry that time
Answered by amitnrw
1

Answer:

4(p+q)(pq +2)

Step-by-step explanation:

8p + 8q + 4p²q + 4pq

Let take common 8 from 8p + 8q

and 4pq as common from 4p²q + 4pq

=8(p+q) + 4pq(p+q)

=(p+q)(8+4pq)

Let take 4 common from 8 =(4*2) and 4pq

=(p+q)4(2+pq)

= 4(p+q)(pq +2)

hence

8p + 8q + 4p²q + 4pq = 4(p+q)(pq +2)

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