Question

Factorize it : x''' - 7x - 6

Answer 1

${x}^{3} - 7x - 6 = 0 \\ {x}^{3} - x - 6x - 6 = 0 \\ {x}^{2} (x - 1) - 6(x - 1) = 0 \\ take \: the \: common \: factor \: out \\ (x - 1)( {x}^{2} - 6) = 0$