Question

factorize (iv)y2 + y2-y-1 if x= 1​

Answer 1

Answer:

${y}^{2} + {y}^{2} - y - 1 \\ \\ = 2 {y}^{2} - y - 1 \\ \\ = 2 {y}^{2} - 2y + y - 1 \\ \\ = 2y(y - 1) + 1(y - 1) \\ \\ = (y - 1)(2y + 1)$

Answer 2

Step-by-step explanation:

${y}^{2} + {y}^{2} - y - 1$

$= 2 {y}^{2} - y - 1$

$= 2 {y}^{2} - 2y + y - 1$

$= 2y(y - 1) + 1(y - 1)$

$= (2y + 1)(y - 1)$