Question

factorize m^2/4+n^2/16-mn/4​

Answer 1

Answer:

$\frac{ {m}^{2} }{4} + \frac{ {n}^{2} }{16} - \frac{mn}{4} \\ = ( { \frac{m}{2} })^{2} + ( { \frac{n}{4} })^{2} - 2 \times \frac{m}{2} \times \frac{n}{4} \\ = ({ \frac{m}{2} } - { \frac{n}{4} })^{2} \\ = ( \frac{m}{2} - \frac{n}{4} ) ( \frac{m}{2} - \frac{n}{4} ) \: are \: the \ \\ required \: factors \: of \: given \: \\ quadratic \: polynomial$