Question

factorize m2+11mn+18n2

Answer 1

m^2+11mn+18n^2
m^2+9mn+2mn+18n^2
m(m+9n)+2n(m+9n)
(m+2n)(m+9n)

Answer 2

here is yours sum explaination,

here m square will remain as it is but we will write their 9mn+2mn because 9+2=11 and 9 multiply by 2 is 18.
$m {}^{2} + 9mn + 2mn + 18n {}^{2}$
now, we will take out the common

$m(m + 9n) + 2n(m + 9n)$
now your answer will be
$(m + 2n) ( m+ 2n)$