Math, asked by nikitamaneshwar198, 2 days ago



Factorize m² (m-n) - mn (n-m)

Please help me​

Answers

Answered by Mysteryboy01
2

=  m² (m-n) - mn (n-m)

=  {m}^{3}  -  {m}^{2}n - m {n}^{2} -  {m}^{2}n

Answered by yassersayeed
1

Answer:

Hence required result will be  m² (m-n) - mn (n-m)=m^{3} -m^{2} n-mn^{2} +m^{2} n

Step-by-step explanation:

In accordance with the information provided in the question,

Given the data in question  m² (m-n) - mn (n-m)

We have to factorize the above equation

We are solving in the following way

As we get,

m^{2} (m-n)-mn(n-m)

The product of negative sign  multiply with  negative sign will make positive result

Example (-)(-)=(+)

m^{2} \times m-m^{2} \times n-mn\times n+mn\times m\\m^{2} \times m-m^{2} n-mn^{2} +m^{2} n\\m^{3} -m^{2} n-mn^{2} +m^{2} n

Hence required result will be  m² (m-n) - mn (n-m)=m^{3} -m^{2} n-mn^{2} +m^{2} n

Similar questions