Question

factorize of x³+3x²+3x+28​

Answer 1

Answer:

(x^2 + x + 7) . (x - 4)

Step-by-step explanation:

Step1:

equation at the end of step 1

(((x^3) - 3x^2) + 3x) - 28

Step 2:

checking for a perfect cube

2.1 x^3 - 3x^2 + 3x -28 is not a perfect cube

we have 2 groups

Group 1: (3x - 28) . (1)

Group 2: (x-3) . (x^2)

The groups have no factor and cannot be added to form a multiplication .

By polynomial roots calculator it can be divided by x-4

By polynomial long division the quotient will be x^2 + x + 7 and remainder = 0

By factorising the quotient we get:

1* 7= 7 but not two factors of 7 whose sum =1

So, The ans. = (x^2+x+7) . (x-4)

Answer 2

Step-by-step explanation:

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