Math, asked by Sir100, 10 months ago

Factorize
P^2-q^2-p+q

Answers

Answered by parvd

Answer:

hey mate!

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Step-by-step explanation:

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p²-q²-p+q

=>(p+q)(p-q)-p+q

=>-1(p+q)(p-q)(q-p)

ans!!

thanks!

Sir100: Ans = (p-q)(p+q)-1

Sir100: (P-q)(p+q-1)

Sir100: Your ans not match

jainsid131: Your answer is wrong .Correct again .Edit it...

Answered by ganesh3533

Answer:

p^2-q^2-p+q

(p-q)(p+q)-(p-q)

( p-q)(p+q-1)

Sir100: How

Sir100: (P+q-1) how cam not understand

ganesh3533: p^2-q^-p+q. p^2-q^2 ke factors (p-q)(p+q). Jo p-q h. usse agar minus Ka common loge -(p-q) bachega phir dono SE (p-q) Ka common loge to bachega (p-q)(p+q-1) hi to bachega

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Factorize P^2-q^2-p+q

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Factorize
P^2-q^2-p+q