Question

factorize:- p-2q-p^2+4q^2

please answer immediately.......

Answer 1

(p - 2q) - p² + 4q²

(p - 2q) + 4q² - p²

(p - 2q) + (2q)² - (p)²

××××××××××
By formula, a²-b²=(a+b)(a-b)
×××××××××××

(p - 2q) + (2q - p)(2q + p)

(p - 2q)(1 - 2p - p)



I hope this will help you



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Answer 2

(p-2q) -(p^2 - 4q^2)

(p-2q) -( p^2 - (2q)^2 )

(p-2q) - (p+2q)(p-2q)

(p-2q)(1-p+2q)


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