Factorize p^3 +p^3 - 1+3pq
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p³+q³-1+3pq
=>(p+q)³-3pq(p+q)-1+3pq
=>(p+q)³-3pq(p+q-1)-1
=>(p+q)³-(3pq(p+q-1)+1)
=>{(p+q)³+(3pq(p+q-1)+1)}{(p+q)³-(3pq(p+q-1)+1)}/{(p+q)³+(3pq(p+q-1)+1)}
=>(p+q)³-3pq(p+q)-1+3pq
=>(p+q)³-3pq(p+q-1)-1
=>(p+q)³-(3pq(p+q-1)+1)
=>{(p+q)³+(3pq(p+q-1)+1)}{(p+q)³-(3pq(p+q-1)+1)}/{(p+q)³+(3pq(p+q-1)+1)}
Namanp:
I don't think that this is the correct answer
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