Question

factorize p^3=(q-r)^2 +q(r-p)+r^2(p-q)^3​

Answer 1

Hey,mate

If a+b+c =0 then a3+b3+c3 = 3abc in this question let a= (p-q) ,b= (q-r) , c= (r-p) than a+b+c = p - q + q- r + r- p = 0 so

If a+b+c =0 then a3+b3+c3 = 3abc in this question let a= (p-q) ,b= (q-r) , c= (r-p) than a+b+c = p - q + q- r + r- p = 0 so (p-q)3 + ( q-r)3+ (r-p)3 = 3 (p-q)(q-r)(r-p)

If a+b+c =0 then a3+b3+c3 = 3abc in this question let a= (p-q) ,b= (q-r) , c= (r-p) than a+b+c = p - q + q- r + r- p = 0 so (p-q)3 + ( q-r)3+ (r-p)3 = 3 (p-q)(q-r)(r-p) This is the shortest way to do these type of questions

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