factorize p^4+q^4+p^2q^2
please explain step by step
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Answer:
(p²+q²+pq)(p²+q²-pq)
Explanation:
p⁴+q⁴+p²q²
= p⁴+q⁴+2p²q²-p²q²
[ add and subtract p²q² ]
=[ (p²)² + (q²)²+2*p²q²]-(pq)²
= (p²+q²)² - (pq)²
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We know the algebraic identity:
a²-b² = (a+b)(a-b)
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= [(p²+q²)+pq][(p²+q²)-pq]
= (p²+q²+pq)(p²+q²-pq)
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mygame10544:
namaste sir
= p⁴+q⁴+2p²q²-p²q²
we cannot take it like this there is no method right?
can u explain sir
p⁴ + q⁴ + p²q² + p²q² - p²q² we take like this
to make it whole square
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