Question

Factorize. (p-q)3+(q-r)3+(r-p)3​

Answer 1

Answer:

Taking (p-q) as a, (q-r) as b, and (r-p) as c, we have a+ b+c = p-q+q-r+r-p = 0. Also we know when a+b+c = 0 then a^3 + b^3 + c^3 = 3 abc. So, (p-q)^3+(q-r)^3+(r-p)^3 = 3 (p-q) (q-r) (r-p)