factorize (p-q)^3 + (q-r)^3 +(r-p)^3
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Answer :
Let us take,
x = p - q, y = q - r and z = r - p
Now, x + y + z
= p - q + q - r + r - p
= 0
We know that,
x³ + y³ + z³ - 3xyz
= (x + y + z) (x² + y² + z² - xy - yz - zx)
⇒ (p - q)³ + (q - r)³ + (r - q)³
- 3 (p - q) (q - r) (r - p)
= 0 × (x² + y² + z² - xy - yz - zx)
⇒ (p - q)³ + (q - r)³ + (r - q)³
= 3 (p - q) (q - r) (r - p),
which is the required factorization
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