Question

factorize p square-pq-6qsquare

Answer 1

Answer:

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Answer 2

${p}^{2} - pq - 6 {q}^{2}$

${p}^{2} - (3 - 2)pq - 6 {q}^{2}$

${p}^{2} - 3pq + 2pq - 6 {q}^{2}$

$p(p - 3q) + 2q(p - 3q)$

$(p - 3q)(p + 2q)$

hope it helps you ✔✔✔✔