Factorize : P(x) =4x^3+3x^2−4x−3
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Answer:
p(x)=4x³+3x²-4x-3
factors of 3=±1,±3
p(1)=4X1+3X1-4X1-3
=4+3-4-3
=7-7
=0
So,x-1 is a factor of 4x³+3x²-4x-3
4x³+3x²-4x-3/x+1=4x²-x-3
4x³+3x²-4x-3=(x+1)(4x²-x-3)
=(x+1)(4x²-4x+3x-3)
=(x+1)[4x(x-1)+3(x-1)]
=(x+1)(x-1)(4x+3). ans
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