factorize p² - 3pq + 2a²
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In Place Of 2a² I Have Taken 2q²
= p² - 3pq + 2q²
= p² - (1 + 2)pq + 2q²
= p² - 1pq - 2pq + q²
= p ( p - q ) - 2q ( p - q )
= ( p - 2q ) ( p - q )
✔✔ Hope it helps ✔✔
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