Question

factorize p²q-pr²-pq+r²​

Answer 1

Answer:

(pq-r²) (p-1)

Step-by-step explanation:

given : p²q-pr²-pq+r²

rearranging like term : p²q-pq-pr²+r²

(taking pq common from first 2 term & r² common from last 2 terms)

= pq(p-1) - r²(p-1)

= (pq-r²) (p-1)