Question

factorize p³-p²q+1/3pq²-1/27q³
$factorize \: {p}^{3 } - {p}^{2} q+ \binom{1}{3 {pq}^{2} } - \binom{1}{27 {q}^{3} }$
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Answer 1

Answer:

Hey buddy here's ur answer !

Step-by-step explanation:

Given: p³-p²q+1/3pq²-1/27q³

Now, first let us simplify the the given equation =>

p3 -p2q + 1/3pq2 -1/27q3

=> (p)3 - (p)2q + 1/3 p(q) 2 - (1/3q) 3. ......( 1 )

=> Here we observe that the whole equation is in the form of

[ (x-y)³= x³-3x²y+3xy²-y³ ]. ........( 2 )

Now let us further simplify it by putting the values of equation ( 1 ) and ( 2 )

=> (1p)³ + 3(1p)²(-1/3q) + 3* (1p)(-1/3q)²+(-1/3q)³ = (1p - 1/3q)³

=> (p-1/3q)³ .............[Final Answer]

Hope it has helped u, if yes do mark as brainliest !

@Sulphuricnitrogen