Question

factorize
p6 - 512q6

Answer 1

p^6-512q^6
=p^6=(p^3)^2
=512q^6=(8^3)^2
So,now:-
{(p^3)^2}-{(8q^3)^2}
W.K.T a^2-b^2=(a-b)(a+b)
=(p^3-8q^3)(p^3+8q^3)
Again, a^3-b^3=(a-b)(a^2+ab+b^2)
a^3+b^3=(a+b)(a^2-ab+b^3)
=(p-8q)(p^2+8pq+64q^2)(p+8q)(p^2-8pq+64q^3)

Answer 2

Answer:

Step-by-step explanation:

p^6-512q^6

=p^6=(p^3)^2

=512q^6=(8^3)^2

So,now:-

{(p^3)^2}-{(8q^3)^2}

W.K.T a^2-b^2=(a-b)(a+b)

=(p^3-8q^3)(p^3+8q^3)

Again, a^3-b^3=(a-b)(a^2+ab+b^2)

a^3+b^3=(a+b)(a^2-ab+b^3)

=(p-8q)(p^2+8pq+64q^2)(p+8q)(p^2-8pq+64q^3)