factorize
p6 - 512q6
Answers
Answered by
41
p^6-512q^6
=p^6=(p^3)^2
=512q^6=(8^3)^2
So,now:-
{(p^3)^2}-{(8q^3)^2}
W.K.T a^2-b^2=(a-b)(a+b)
=(p^3-8q^3)(p^3+8q^3)
Again, a^3-b^3=(a-b)(a^2+ab+b^2)
a^3+b^3=(a+b)(a^2-ab+b^3)
=(p-8q)(p^2+8pq+64q^2)(p+8q)(p^2-8pq+64q^3)
=p^6=(p^3)^2
=512q^6=(8^3)^2
So,now:-
{(p^3)^2}-{(8q^3)^2}
W.K.T a^2-b^2=(a-b)(a+b)
=(p^3-8q^3)(p^3+8q^3)
Again, a^3-b^3=(a-b)(a^2+ab+b^2)
a^3+b^3=(a+b)(a^2-ab+b^3)
=(p-8q)(p^2+8pq+64q^2)(p+8q)(p^2-8pq+64q^3)
Answered by
10
Answer:
Step-by-step explanation:
p^6-512q^6
=p^6=(p^3)^2
=512q^6=(8^3)^2
So,now:-
{(p^3)^2}-{(8q^3)^2}
W.K.T a^2-b^2=(a-b)(a+b)
=(p^3-8q^3)(p^3+8q^3)
Again, a^3-b^3=(a-b)(a^2+ab+b^2)
a^3+b^3=(a+b)(a^2-ab+b^3)
=(p-8q)(p^2+8pq+64q^2)(p+8q)(p^2-8pq+64q^3)
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